yassinesayedahmad1
23.07.2019 •
Mathematics
If cos 0 = -4/9 with 0 in quadrant ii, find sin 0
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Ответ:
X= -4 and r= 9 (radius is also the hypotenuse)
In quadrant II y is positive
X^2 +y^2 = r^2
-4^2 + y^2 = 9^2
16 + y^2 = 81
Y^2 = 81-16
Y^2 = 65
Y= sqrt65
Sin0= sqrt65/9
Ответ:
This is beyond me sheesh. Sorry Lol
Step-by-step explanation: