gwendallinesikes
20.09.2019 •
Mathematics
If cosθ=3/5 and θ is in quadrant iv, sin2θ=?
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Ответ:
-
Step-by-step explanation:
Using the double angle identity
sin2x = 2sinxcosx and
sin²x + cos²x = 1 ⇒ sinx = ±
Since Θ is in fourth quadrant then sinΘ < 0
sinΘ =-
= -
= -
= -
= - 
Hence
sin2Θ = 2 × -
× 
= - 
Ответ:
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