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mistiehaas
31.03.2020 •
Mathematics
If \csc \theta =\sqrt{2}cscθ= 2 and the reference angle of \thetaθ is 45^\circ 45 ∘ , find both angles in degrees from 0^\circ \theta < 360^{\circ}0 ∘ ≤θ<360 ∘ and both angles in radians from 0 \le \theta < 2\pi.0≤θ<2π
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Ответ:
Step-by-step explanation:
Given that,
Degree to radian,
or,![1^\circ =\frac{\pi}{180}](/tpl/images/0572/1362/ef7fb.png)
csc is reciprocal function of sin.
Sin is positive only first co-ordinate and second co-ordinate.
So, csc is also positive only first co-ordinate and second co-ordinate.
Since![0^\circ\leq \theta\leq 360^\circ](/tpl/images/0572/1362/a1a75.png)
Therefore
Ответ:
3 x radius = 3r