If f(x) = -x + 4 and g(x) = x^2 - 5, then g(f(3)) = ?
A) -8
B) -4
C) -3
D) 0

B) -4

Step-by-step explanation:

To solve g(f(3)), we first have to solve f(3):

Since f(x) = -x +4 , f(3) = -3 + 4 = 1

Now we have to solve g(1) , since that is what f(3) left us;

Since g(x) = x^2 - 5 , g(1) = 1^2 - 5 = 1 - 5 = -4

(1,1) does satisfy

x - 8y ≤ 9

- 7x + 5y < 4

Step-by-step explanation:

Well, first we need to plug in (1,1) into,

x - 8y ≤ 9

- 7x + 5y < 4

→ 1 - 8(1) ≤ 9

- 7(1) + 5(1) < 4

1 - 8 ≤ 9

-7 + 5 < 4

-7 ≤ 9

-2 < 4

Thus,

(1,1) does satisfy

x - 8y ≤ 9

- 7x + 5y < 4.

Hope this helps :)