If h(x)=(fog)(x) and h(x)= √x+5
find g(x)
if f(x)= √x+2

9514 1404 393

Step-by-step explanation:

Compared to vertex form ...

  y = a(x -h)^2 +k

we find that a=-3, (h, k) = (0, 0). That is, the vertex is (0, 0).

A parabola whose vertex is on the x-axis has that as its only x-intercept. (The x-intercept (vertex) is NOT in the solution set.)

The negative leading coefficient tells you the graph opens downward. The y < ( ) comparison tells you shading is below the boundary line, which is dashed. Below a downward-opening parabola is inside the parabola.

The two offered points are on the x-axis, so not in the solution set.