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michaelswagout
28.01.2020 •
Mathematics
If lim as x approaches 3 at f(x)/(2x-6)=f'(3)=0 which of the following must be true? i) (3,0) is a critical point of f(x). ii) f(x) has a local minimum at x=3 iii) f(x) is continuous at x=3 a) i only b) ii only c) iii only d) i and iii only e)i ii and iii
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Ответ:
F'(3)=0 so there is a critical point at x=3.
We don't know if the point at x=3 is a min or max since the original function is not given
In order for a function to be differentiable at a point it must also be continuous by definition.
Ответ: