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bry662
22.09.2019 •
Mathematics
If michael jordan has a vertical leap of 1.29 m, then what is his takeoff speed and his hang time
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Ответ:
u² - 2gh = 0
where
g = 9.8 m/s², acceleration due to gravity.
Because h = 1.29 m, therefore
u² = 2*9.8*1.39 = 27.244
u = 5.2196 m/s
Also, the time of flight, t, required when the vertical take-off speed is u is given by
ut - 0.5gt² = 0.
Therefore
5.2196t - 0.5*9.8*t² = 0
5.2196t - 4.9t² = 0
t(5.2196 - 4.9t) = 0
t = 0, or t = 5.2196/4.9 = 1.0652 s
t = 0 corresponds to take-off.
t = 1.0652 s corresponds to landing.
The hang time is 1.0652 s.
Take-off speed = 5.22 m/s (nearest hundredth)
Hang time = 1.065 s (nearest thousandth)
Ответ:
bet
Step-by-step explanation: