If one root of the equation x^2+px+8=0 is -2, then p=

Question :-

If one root of the equation is -2 then find the value of P.

In this question, we are given the root of the equation which means we have the value of x.By putting given root in equation and equating it with -2 we can find the value of p.

Henceforth, p will be 6.

Given :

If one root of the equation x²+ px + 8 = 0 is -2, then find the value of p.

Understanding the question :

Here, In this question, it is given the root of the equation which means we have the value of x.Now we are to put the value of x which is (-2) and by evaluating it we could find the value of p.

Solution :

Now putting the value of x in the equation :

Adding the like terms :

Transposing 12 to the right side thus it becomes negative :

Cancelling (-) from both sides :

3/12, or 1/4. This is because 1/6=2/12, and 1/3=4/12. 2/12+4/12+3/12=9/12, 12/12-9/12=3/12, and 3/12 simplified is 1/4. Hope that helped!