If sin 0=3/5, what is the measure of the angle?
a.
53.1º
b.
36.9º
c.
30.1º
d.
59º

Downhill:10mph   Uphill:5mph

Step-by-step explanation:  

We are looking for Dennis’s downhill speed.

Let  

r=

 Dennis’s downhill speed.

His uphill speed is  

5

miles per hour slower.

Let  

r−5=

Dennis’s uphill speed.

Enter the rates into the chart. The distance is the same in both directions,  

20

miles.

Since  

D=rt

, we solve for  

t

and get  

t=

D

r

.

We divide the distance by the rate in each row and place the expression in the time column.

Rate

×

Time

=

Distance

Downhill

r

20

r

20

Uphill

r−5

20

r−5

20

Write a word sentence about the time.

The total time traveled was  

6

hours.

Translate the sentence to get the equation.

20

r

+

20

r−5

=6

Solve.

20(r−5)+20(r)

40r−100

0

0

0

=

=

=

=

=

6(r)(r−5)

6

r

2

−30r

6

r

2

−70r+100

2(3

r

2

−35r+50)

2(3r−5)(r−10)

Use the Zero Product Property.

(r−10)=0

r=10

(3r−5)=0

r=

5

3

The solution  

5

3

is unreasonable because  

5

3

−5=−

10

3

and his uphill speed cannot be negative. So, Dennis's downhill speed is  

10

mph and his uphill speed is  

10−5=5

mph.

Check. Is  

10

mph a reasonable speed for biking downhill? Yes.

Downhill:

10 mph

5 mph⋅

20 miles

5 mph

=20 miles

Uphill:

10−5=5 mph

(10−5) mph⋅

20 miles

10−5 mph

=20 miles

The total time traveled was  

6

hours.

Dennis’ downhill speed was  

10

mph and his uphill speed was  

5

mph.