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gutierrezaandrea56
28.01.2020 •
Mathematics
If sin θ = 5/6 , what are the values of cos θ and tan θ? (2 points)
cos θ = ± 11/36; tan θ = ± 1/11
cos θ = ± ; tan θ = -1/11
cos θ = ± 11/6; tan θ = -5/11
cos θ = ± ; tan θ = ± 5
can someone explain step-by-step how to do this? i'm totally lost
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Ответ:
adj^2 = hyp^2 - opp^2
adj^2 = 36 -25
adj^2 = 11
adjacent = sq root (11)
cosine theta = adj / hyp = sq root (11) / 6
tangent theta = opp / adj = 5 / sq root (11)
Ответ:
Step-by-step explanation:
Since, here![sin\theta=5/6](/tpl/images/0478/7121/1704b.png)
And we know that![cos\theta =\sqrt{1-sin^2\theta}](/tpl/images/0478/7121/5763e.png)
So![cos\theta=\sqrt{1-(5/6)^2} =\sqrt{1-25/36} =\sqrt{11/36} =\pm\frac{\sqrt{11} }{6}](/tpl/images/0478/7121/c5eae.png)
Thus,![cos\theta=\pm\frac{\sqrt{11} }{6}](/tpl/images/0478/7121/00d24.png)
Now, we know that![tan\theta=sin\theta/cos\theta=\frac{5/6}{\pm \sqrt{11}/6 } =\frac{5}{\pm \sqrt{11} }](/tpl/images/0478/7121/92063.png)
Thus,![tan\theta=\frac{5}{\pm \sqrt{11} }](/tpl/images/0478/7121/6e9ea.png)
Ответ: