If tan=15/8 then
A.csc=17/15
B.cos=15/7
C.cot=8/15
D.sec=17/8

Step-by-step explanation:

cos=8/17

that's all

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the hawk has flow 824.62 meters southwest of the mountain peak.

Step-by-step explanation:

In order to find the distance we need to use the Pythagoras theorem

d^2 = 800^2 + 200^2

d= 824.6 m

we can find the direction by using the eq for a tangent

he opposite side is 200 m and the adjacent side is 800m

tan theta = opposite / adjacent

theta = arc tan (800/200)

The hawk is at a distance of 824.6m flying at an angle 76 degrees NE of the mountain peak.

The final location will be southwest of the mountain peek.

a2+b2=c2

a = 200

b= 800

c = √(2002+8002) = 824.62

So the hawk has flow 824.62 meters southwest of the mountain peak.