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gabw2758
21.10.2020 •
Mathematics
If tan(x)=3/5 and sin(x)>0, what is sin(2x)?
With STEPS PLEASE AND NO TROLLING.
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Ответ:
sin2x =![\frac{30}{34}](/tpl/images/0827/5675/6ccc4.png)
Step-by-step explanation:
Given
tanx =
= ![\frac{opposite}{adjacent}](/tpl/images/0827/5675/89ea1.png)
This is a right triangle with legs 3 and 5
Let the hypotenuse be h , then using Pythagoras' identity
h² = 3² + 5² = 9 + 25 = 34 ( take the square root of both sides )
h =![\sqrt{34}](/tpl/images/0827/5675/2f895.png)
Thus
sinx =
= ![\frac{3}{\sqrt{34} }](/tpl/images/0827/5675/ab985.png)
cosx =
= ![\frac{5}{\sqrt{34} }](/tpl/images/0827/5675/88582.png)
Hence
sin2x = 2sinxcosx = 2 ×
×
=
= ![\frac{30}{34}](/tpl/images/0827/5675/6ccc4.png)
Ответ:
i edited the answer. hope it helps. if it isn't ryt tell me plz
Ответ:
56 weeks in 1 yr
8*56= glasses a yr