189652
02.08.2021 •
Mathematics
If the density of the wood is 3 pounds per cubic foot and if the weight of the solid is
360 pounds, what is the width, w, in feet, of the solid?
(A) 5.0
(B) 2.5
(C) 2.4
(D) 1.5
The area of the triangular face of the solid is 48 if that helps
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Ответ:
The width in feet of the given solid is 1.136
Density is defined as the ratio of the mass per unit volume
Density = Mass/Volume
Given
Weight = 360 pounds
Density = 3 pounds per cubic foot
Get the mass;
Since W = mg
m = W/g
m = 360/2.2
m =163.64 lbm/kg
Get the volume
From the formula;
Volume = Mass/Density
Volume = 163.64 /3
Volume = 54.55 ft³
Next is to get the width
Volume of the triangular prism = Base Area * Width
Base Area = 48ft²
54.55 = 48w
w = 54.55/48
w = 1.136
Hence the width of the solid in feet is 1.136ft
Learn more on how to calculate density here
Ответ:
Step-by-step explanation:
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