If the equation of a circle is (x - 2)2+(-6)2 = 4, the center is point (2,6).
m

If you meant to write (x-2)^2 + (y-6)^2 = 4, then the center is (2,6). The statement would be true.

This is because the general form (x-h)^2 + (y-k)^2 = r^2 describes a circle centered at (h,k) with radius r. In this case, h = 2, k = 6, r = 2. Note how r^2 = 4 so r^2 = 2^2 leads to r = 2.

A'(-3, -2)

B'(-2, -1)

C'(-2, -2)

Step-by-step explanation:

The translation is (x - 7, y + 1).

That means subtract 7 from the x-coordinate and add 1 to the y-coordinate of each point.

Point A is (4, -3).

Subtract 7 from the x-coordinate 4 to get -3.

Add 1 to the y-coordinate -3 to get -2.

For point A, you get A'(-3, -2) after the translation.

Do the same with points B and C.

B(5, -2) ---> B'(5 - 7, -2 + 1) = B'(-2, -1)

C(5, -3) ---> C'(5 - 7, -3 + 1) = C'(-2, -2)