jbot9050
28.03.2021 •
Mathematics
If the perimeter of a rectangle is 26x^2+16x+10 and the length is 8x^2+6x+4, what is the width?
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Ответ:
Here is the set up:
P = 2L + 2W
P = 2(26x^2+16x+10) + 2(8x^2+6x+4)
Simplify the right side to find P.
Ответ:
reflection
Step-by-step explanation: