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HahaHELPP
19.09.2019 •
Mathematics
If the perimeter of a rectangular house is 44 yards, and the length is 36 feet, what is the width of the house?
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Ответ:
P = 2L + 2W
2W = P - 2L
W = P/2 - L
P = 44 yards ( 3 ft / 1 yard ) = 132 ft
L = 36 ft
Substituting the values given:
W = 132/2 - 36
W = 30 feet
Ответ:
23456789
Step-by-step explanation: