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tez87
03.07.2019 •
Mathematics
If the point (-1/2, y ) lies on the line whose equation is 2 x - 3 y = 6, what is the value of y ? -7/3 -5/3 7/3
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Ответ:
Hi there!
In order to find the value of "y" when "x" is equal to -1/2, you need to replace the "x" in your equation with it's value (which is -1/2) and then solve the equation by isolating "y" :
2 (-1/2) - 3y = 6
Add 3y to each side of the equation
2(-1/2) = 6 + 3y
Subtract 6 from each side of the equation
2(-1/2) - 6 = 3y
-1 - 6 = 3y
-7 = 3y
Divide each side of the equation by 3
-7/3 = y
There you go! I really hope this helped, if there's anything just let me know! :)
Ответ:
Step-by-step explanation:
4(2x+3)-5y
=8x+12-5y
Sum means addition: 2x+3
Term: Term could be a single number , variable, or the product of both. we have 8x, 12,-5y
Product ( multiplication): we have 4(2x+3), 2 multiplied by x(2x), 5y
Factor(part of a product : factor of 8x=8, x, 2 and 4
Factor of -5y=-5 and y
Factor of 12=2,4,6
Quotient ( it is the result obtained by dividing one quantity by another)= Not present in the expression. The expression doesn't have a division
Coefficient : is a number which is in product with variable.
Coefficient of 8x=8
Coefficient of -5y=-5
Coefficient of 12=12