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cragajjar2
26.04.2020 •
Mathematics
.If the sizes of interior angles of a pentagon are 2xDEGREE, 3xDEGREE, 4xDEGREE, 5xDEGREE
and 6xDEGREE, find the largest interior angle of the pentagon.
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Ответ:
Explanation:
S = 180(n-2) is the formula used to find the sum of the interior angles for any convex polygon. In this case, n = 5 sides for a pentagon
S = 180(n-2) = 180(5-2) = 180*3 = 540 degrees is the sum of the angles of the pentagon.
The angles {2x, 3x, 4x, 5x, 6x} must add to 540
2x+3x+4x+5x+6x = 540
20x = 540
x = 540/20
x = 27
Which means
2x = 2*27 = 54
3x = 3*27 = 81
4x = 4*27 = 108
5x = 5*27 = 135
6x = 6*27 = 162 is the largest interior angle
Ответ:
162°
Step-by-step explanation:
Total interior angle of Pentagon:
(5 - 2) × 180
540
2x + 3x + 4x + 5x + 6x = 540
20x = 540
x = 27
Largest angle: 6x
6(27)
162
Ответ:
The Answer You Are Looking For Is 2x + 22
Hope This Helps!
-mojo jojo x