sonyalehardez
10.07.2019 •
Mathematics
If town a has a yearly population of 3,225 and is growing by 100 people each year and town b has a yearly population of 3,300 and is growing by 75 people per year, after how many years will the two populations be equal?
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Ответ:
so Town A arithmetic progressive expression =
tn=3225+(n-1)100
tn= 3225+100n-100 = 3125+100n
for Town B you have
tn= 3300+(n-1)75 = 3300+75n-75 = 3225+75n
equating both A and B
3125+100n=3225+75n
100n-75n=3225-3125
25n= 100
n=100÷25=4
n=4years
they'll be equal after 4years
Ответ:
Solve the following inequality. -3.55g 5-28.4. Which graph shows the correct solution? 3 4 5 6 7 8 9 10 11 12 13 3 4 5 6 7 8 9 10 11 12 13 3 4 5
Step-by-step explanation: