ZVSaniya0420

ZVSaniya0420

08.07.2019 •

Mathematics

If triangle ghi is congruent to triangle jkl, weich statement is not true?
(options pictured)

If triangle ghi is congruent to triangle jkl, weich statement is not true? (options pict

Solved

Show answers

Ответ:

taykola

02.04.2023

$\sigma_1 = 0.08$ --- Location 1

$\sigma_2 = 0.34$ --- Location 2

Step-by-step explanation:

Given

See attachment for the given data

Required

The standard deviation of each location

For location 1

First, calculate the mean

$\bar x_1 =\frac{\sum x}{n}$

So, we have:

$\bar x_1 =\frac{30.40+30.20+30.30+30.40+30.30}{5}$

$\bar x_1 =\frac{151.60}{5}$

$\bar x_1 =30.32$

The standard deviation is calculated as:

$\sigma_1 = \sqrt{\frac{\sum(x - \bar x_1)^2}{n-1}}$

$\sigma_1 = \sqrt{\frac{(30.40 - 30.32)^2+(30.20 - 30.32)^2+(30.30 - 30.32)^2+(30.40 - 30.32)^2+(30.30 - 30.32)^2}{5-1}}$

$\sigma_1 = \sqrt{\frac{0.028}{4}}$

$\sigma_1 = \sqrt{0.007}$

$\sigma_1 = 0.08$

For location 2

First, calculate the mean

$\bar x_2 =\frac{\sum x}{n}$

So, we have:

$\bar x_2 =\frac{30.10+30.90+30.20+30.70+30.30}{5}$

$\bar x_2 =\frac{152.2}{5}$

$\bar x_2 =30.44$

The standard deviation is calculated as:

$\sigma_2 = \sqrt{\frac{\sum(x - \bar x_2)^2}{n-1}}$

$\sigma_2 = \sqrt{\frac{(30.10-30.44)^2+(30.90-30.44)^2+(30.20-30.44)^2+(30.70-30.44)^2+(30.30-30.44)^2}{5-1}}$

$\sigma_2 = \sqrt{\frac{0.472}{4}}$

$\sigma_2 = \sqrt{0.118}$

$\sigma_2 = 0.34$

To determine the organic material in a dried lake bed, the percent carbon by mass is measured at two

0,0(0 оценок)

Ask your question to the AI advisor

Ai-bot is an expert in any field and is the perfect companion for reliable and useful answers and advice on a variety of topics, including science, history, technology, art, sports, health, culture and more.

Ask your question

More tips

Answers on questions: Mathematics

Ask an AI advisor a question

I want advice