If two polynomial equations have real solutions, then will the equation that is the result of adding, subtracting, or multiplying the two polynomial equations also have solutions?

No. A polynomial equation in one variablel ooks like P(x) = Q(x), where P and Q are polynomials.

Consider polynomial equations x^2 = 3 and x^2 = 1.

Obviously they have real solutions.

Subtract the two polynomial equations:

(x^2 - x^2) = (3 - 1)

0 = 2...

We get the polynomial equation 0 = 2. We call this a polynomial equation because single constants are also by definition polynomials.

Obviously 0 = 2 has no real solution.

equation that represent this situation is 0.65 x + 3 = 21

Step-by-step explanation:

given data

profit = $21.00

sold = $0.75

received a tip = $3

buy plastic cup = $0.10

solution

we consider here number of cups = x

so here equation will be here number of cup price of 1 cup plus tip from a neighbor equal to selling profit

x ( 0.75 - 0.10 ) + 3 = 21   1

0.65 x + 3 = 21

so equation that represent this situation is 0.65 x + 3 = 21