If Wade has 2 times as many dimes as quarters and they have a combined value of 270 cents, how many of each coin does he have?

Step-by-step explanation:

If he has twice the number of dimes as quarters, then obviously he has more dimes than quarters. The expression that represents that is

d = 2q

That relates the NUMBER of coins; now we need one that relates the VALUE which is a dollars and cents thing. We know that the combined value of the coins is $2.70. The expression that represents this is

.1d + .25q = 2.70 because dimes are worth .10 and quarters are worth .25

Subbing the first equation into the second gives us

.1(2q) + .25q = 2.70 and

.2q + .25q = 2.70 and

.45q = 2.70 so

q = 6

This means he has 6 quarters. If the umber of dimes is twice as much, then d = 2(6) and d = 12.

He has 6 quarters and 12 dimes