Arealbot
09.12.2019 •
Mathematics
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if x²+4x+y²-6y-12=0 is the equation of a circle, the length of the radius is
1. 25
2. 16
3. 5
4. 4
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Ответ:
an equation of the circle Center at the A(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
x²+4x+y²-6y-12=0
(x²+4x+2²) -2² +(y²-6y+3²)-3²-12 = 0
(x+2)² +(y-3)² = 25 = 5² the length of the radius is : 5 (answer :3 )
Ответ:
57 and 76
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