xaniawashington
25.06.2019 •
Mathematics
If x/9 < 2/5 and x is a positive integer, how many distinct values are possible for x?
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Ответ:
3
Step-by-step explanation:
Solving the inequality gives ...
x/9 < 2/5
x < 18/5 . . . . multiply by 9
Applying the problem restrictions, we have ...
0 < x < 3.6 . . . . . x is an integer
Solutions are {1, 2, 3}. There are 3 distinct possible values for x.
Ответ: