Mathematics: If (x – ½) and (x-2) are the factors of px2+5x + r, find p and r . Also find p -r .

If (x – ½) and (x-2) are the factors of px2+5x + r,

Ответ:

khalaflaf9381

31.01.2022

Mathematics

p = -2, r = -2 and p-r = 0.

Step-by-step explanation:

(x - 1/2)(x - 2)

= x^2 - 2x - 1/2x + 1

= x^2 - 5/2x + 1

= 2x^2 - 5x + 2

= -2x^2 + 5x - 2

Comparing this with

px^2 + 5x + r

we see that p = -2, r = -2 and p-r = 0.

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Ответ:

dbn4everloved

08.01.2023

Mathematics

$\bf \textit{area of a sector of a circle}\\\\ A=\cfrac{\pi \theta r^2}{360}~~ \begin{cases} r=&radius\\ \theta =&angle~in\\ &degrees\\ \cline{1-2} r=&6\\ \theta =&87 \end{cases}\implies A=\cfrac{\pi (87)(6)^2}{360}\implies A=\cfrac{87\pi }{10} \\\\\\ A\approx 27.332\implies \stackrel{\textit{rounded up}}{A=27.3}$

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If (x – ½) and (x-2) are the factors of px2+5x + r, find p and r . Also find p -r .

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