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rosanaboyd7
16.10.2019 •
Mathematics
If y varies directly as x, and y is 400 when x is r and y is r when x is 4, what is the numeric constant of variation in this relation? 10 40 100 198
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Ответ:
400=kr (1)
r=4k (2)
400=k(4k)=4k^2
k^2=400/4=100
k=sqrt(100)=10
so k=10 is your answer please mark as brainliest answer
Ответ:
400=m*r
400/m=r
r=m*4
400/m=m*4
400/4=m*m
100=m*m
100^(1/2)=m
10=m
y=10*x
Ответ:
1. consider right triangle adc. in this triangle cd=4 cm and m∠acd=180°-m∠acb=180°-120°=60°. then m∠cad=180°-m∠adc-m∠acd=180°-90°-60°=30°. the leg that is opposite to the angle with measure 30° is half of the hypotenuse, then ac=8 cm.
2. consider isosceles triangle abc. ab is its base, the angles adjacent to the base of isosceles triangle are congruent, then
also ac=cb=8 cm.
3. consider right triangle adb. draw the altitude dh to the hypotenuse ab. this altitutde divides right triangle adb into two right triangles adh and bdh.
4. consider right triangle dbh. in this triangle db is hypotenuse and db=cd+cb=4+8=12 cm. the leg dh is opposite to the angle b with measure 30°, then dh is half of the hypotenuse db. thus, dh=12: 2=6 cm.
answer: 6 cm