mwilliams457
27.01.2020 •
Mathematics
If y(x) = -2x2+3 and v(x) = x, what is the range of (jov(x)?
(3.00)
(-60,3)
0 (0o,00)
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Ответ:
The answer to your question is (-∞, 3)
Step-by-step explanation:
Data
y(x) = -2x² + 3
v(x) = x
Process
1.- Evaluate y(x) in v(x)
yov(x) = -2(x)² + 3
yov(x) = -2x² + 3
2.- Graph the function
In the graph we observe that the posible values of "y" are from (-∞, 3) that is the range.
Ответ:
6+8 is 14
Step-by-step explanation: