Mathematics: If you are smart me with this problem. i will give you extra points

If you are smart me with this problem. i will

Ответ:

malakyi1

02.01.2022

$a_{n} = 2a_{n-1} + 3$

$a_{1} = 2$

$a_{2} = 2a_{2-1} + 3 = 2a_{1} + 3 = (2*2) + 3 = 4 + 3 = 7$

$a_{3} = 2a_{3-1} + 3 = 2a_{2} + 3 = (2*7) + 3 = 14 + 3 = 17$

$a_{4} = 2a_{4-1} + 3 = 2a_{3} + 3 = (2*17) + 3 = 34 + 3 = 37$

$a_{5} = 2a_{5-1} + 3 = 2a_{4} + 3 = (2*37) + 3 = 74 + 3 = 77$

Hence, the first five terms are 2, 7, 17, 37, 77.

0,0(0 оценок)

Ответ:

hei40563273

15.03.2023

Mathematics

Highlight the correct response to each question.

0,0(0 оценок)

If you are smart me with this problem. i will give you extra points

Ответ:

Ответ:

Ask your question to the AI advisor

More tips

Answers on questions: Mathematics

Ask an AI advisor a question