Mathematics: Ill give brainliest to first answerwhich of the following is an equivalent form of the compound inequality −44 −2x − 8 ≥ −8? −2x − 8 −44 and −2x − 8 ≥ −8−2x −44 and −8 ≥ −8 −2x − 8 −44 and −2x − 8 ≤ −8 −2x − 8 −44 and −2x − 8 ≥ −8

Ill give brainliest to first answerwhich of the

sophiateaches053

31.12.2021

$-44 -2x - 8 \geq -8 | \cdot(-1)\\44 < 2x + 8 \leq 8 | : 2\\22 < x + 4 \leq 4\\18 < x \leq 0 = x \in \emptyset$

$-2x -8 -44|\cdot(-1) \ \ -2x - 8 \geq -8|\cdot(-1)\\2x + 8 < 44 \ \ 2x + 8 \leq 8\\x < 18 \ \ x \leq 0 = x \in (-\infty, 0]$

$-2x -44 \ -8x \geq -8\\x < 22 \ \ x \leq 1 = (-\infty, 1]$

$-2x - 8 < -44|\cdot(-1/2) \ \ -2x - 8 \leq -8|\cdot(-1/2)\\x + 4 22 \ \ x + 4 \geq 4\\x 18 \ \ x \geq 0 = x \in (18, \infty)$

$-2x - 8 < -44|\cdot(-1/2) \ \ -2x - 8 \geq - 8|\cdot(-1/2)\\x + 4 22 \ \ x + 4 \leq 4\\x 18 \ \ x \leq 0, = x \in \emptyset$

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ayoismeisalex

15.08.2020

4th street

Step-by-step explanation:

Because the avenues in a particular city run north to south and are numbered consecutively with 1st avenue at the western

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