KAMOO3X
04.02.2020 •
Mathematics
Im having trouble with this problem, can anyone out, i'll rate brainliest!
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Ответ:
18 divided by 3 is 6.
20 divided by 5 is 4.
35 divided by 5 is 7.
54 divided by 6 is 9.
30 divided by 6 is 5.
Ответ:
1. 7
2. 6
3. 4
4. 7
5. 9
6. 5
Step-by-step explanation:
1. Find 63 in the table. Its column and row is 9 and 7. Since you are dividing by 9 then the solution is 7.
2. Find 18 in the table. It appears more than once. But its being divided by 3. Its column and row is 3 and 6. Since you are dividing by 3 then the solution is 6.
3. Find 20 in the table. Its column and row is 5 and 4. Since you are dividing by 5 then the solution is 4.
4. Find 35 in the table. Its column and row is 5 and 7. Since you are dividing by 5 then the solution is 7.
5. Find 54 in the table. Its column and row is 6 and 9. Since you are dividing by 6 then the solution is 9.
6. Find 30 in the table. Its column and row is 6 and 5. Since you are dividing by 6 then the solution is 5.
Ответ:
6, 8, 10 and 12 years
Step-by-step explanation:
I guess you need to find their ages. This can be done by solving an algebraic equation as follows:
Let x years be the age of the youngest child. Then the ages of the other 3 are x+2, x+4 and x+6 years because they were born at 2 year intervals. So we have the equation:
x + x + 2 + x + 4 + x + 6 = 36
4x + 12 = 36
4x = 24
x = 6
so their ages are 6, 8, 10 and 12 years