In 1985, the cost of clothing for a certain family was $620. in 1995, 10 years later, the cost of clothing for this family was $1,000. assuming the cost increased linearly, what was the cost of this family’s clothing in 1991?

The cost of this family’s clothing in 1991 is $ 848.

Step-by-step explanation:

Given,

The cost of clothing is increasing linearly,

Let the equation that represent the cost of clothing ( in dollars ) after x years since 1985,

y = mx + c

Given, for x = 0, y = 620,

⇒ 620 = m(0) + c

⇒ c = 620,

The number of years from 1985 to 1995 = 10 years,

So, if x = 10, y = 1000,

1000 = 10(m) + c

1000 = 10m + 620

380 = 10m

⇒ m = 38,

Hence, the function that represents the cost of clothing would be,

y = 38x + 620

If x = 6,

y = 38(6) + 620 = 848

Therefore, the cost of this family’s clothing in 1991 is $ 848.

C. Yes; he will practice a total of 2 7 12 hours, and 2 7 12 > 2 1 2 .

Step-by-step explanation: