Mathematics: In 1985, there were 285 cell phone subscribers in Arlington. The number of subscribers increased by 75% per year since 1985. Find the number of subscribers in 2008.

In 1985, there were 285 cell phone subscribers - id19852856323194, litwork5885

reecedstceklein

25.01.2022

The number of subscribers in 2008 is 110,845,988

Step-by-step explanation:

The number of cell phone subscribers in Arlington, in t years after 1985, can be modeled by the following equation.

$N(t) = N(0)(1+r)^{t}$

And which N(0) is the number of subscribers in 1985 and r is the rate it increases per year, as a decimal.

In 1985, there were 285 cell phone subscribers in Arlington.

This means that N(0) = 285

The number of subscribers increased by 75% per year since 1985.

This means that r = 0.75

$N(t) = 285(1.75)^{t}$

Find the number of subscribers in 2008.

2008 is 2008-1985 = 23 years after 1985. So we have to find N(23).

$N(23) = 285(1.75)^{23} = 110,845,988$

The number of subscribers in 2008 is 110,845,988

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zhellyyyyy

28.12.2021

(x-1)(5x^2-7)

Hope this helps!

Step-by-step explanation:

have

great day

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