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124319
14.03.2022 •
Mathematics
In 1990 an egg cost 2c less than in 1991. In 1992 an egg cost 4c more than in 1991. The cost of 11 eggs in 1990 was the same as the cost of 8 eggs in 1992. Find the cost of an egg in 1991. (Hint: let the 1991 cost of an egg be n cents. Express the 1990 and 1992 costs in terms of n)
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Ответ:
See below.
Step-by-step explanation:
1.
(10 * 20)/(20 + 30) = 200/50 = 4
2. a.
Factors of 30: 1, 2, 3, 5, 6, 10, 15, 30
Factors of 40: 1, 2, 4, 5, 8, 10, 20, 40
2. b.
10
3.
{-1, -3, -5, -7, ... }
4.
407,006,962
5.
1, 2, 3, 4, 5, 6, 10
6.
-7 > -11
Negative seven is greater than negative eleven.
7.
2, 3, 4, 6, 8, 9
8.
-4 -3 -2 -1 0 1 2 3 4
<++<++++O++>
Start at the 2, shown by the open circle. Draw a segment to the left 5 units long to subtract 5. You end up at -3.
9.
6400 =
= 6000 + 400 + 0 + 0
= 6 * 1000 + 4 * 100 + 0 * 10 + 0 * 1
10.
x + $4.60 = $10.00
x + $4.60 - $4.60 = $10.00 - $4.60
x = $5.40
11.
p - 3850 = 4500
p - 3850 + 3850 = 4500 + 3850
p = 8350
12.
8z = $50.00
8z/8 = $50.00/8
z = $6.25
13.
I don't see an equation.