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moranmar2283
20.07.2019 •
Mathematics
In 1995, 70% of all children in the u.s. were living with both parents. if 25 children were selected at random in the u.s., what is the probability that at most 10 of them will be living with both of their parents? round your answer to 4 decimal places.
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Ответ:
0.0018
Step-by-step explanation:
Binomial distribution formula :-
Given : The probability that a child in the U.S. was living with both parents : p=0.70 ; q=1-0.70=0.30
If 25 children were selected at random in the U.S.,then the probability that at most 10 of them will be living with both of their parents will be :-
Hence, the probability that at most 10 of them will be living with both of their parents is 0.0018.
Ответ:
18z 2+17z+4
Step-by-step explanation:
it hard try to give more point