Mathematics: In 2003, the population of zimbabwe was about 12.6 million people, in which is 1 million more than 4 times the population in 1950. write and solve an equation to find the approximate population p of zimbabwe in 1950

Step-by-step explanation:We want to find the sum of We can rewrite this asThis becomes;Recall that;This implies that;Combine like terms:...

In 2003, the population of zimbabwe was about - id2003126826055, chuyyoshy092714

ronaldo22

08.07.2020

a= 2002 population

x= 1950 population

a=x*4+1,000,000

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riri95

15.03.2021

$4 \sqrt{2} i$

Step-by-step explanation:

We want to find the sum of

$\sqrt{ - 2} + \sqrt{ - 18}$

We can rewrite this as

$\sqrt{ 2 \times - 1} + \sqrt{ 18 \times - 1}$

This becomes;

$\sqrt{2} \times \sqrt{ - 1} + \sqrt{18} \times \sqrt{ - 1}$

Recall that;

$i = \sqrt{ - 1}$

This implies that;

$\sqrt{2} i + 3 \sqrt{2} i$

Combine like terms:

$4 \sqrt{2} i$

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