In a 3-digit number, the humdrends digit is one more than the ones digit and the tens digit is twice the hunderends digit. If the sum of the digits. Is. 11, find the number

362

Step-by-step explanation:

let the digits that make up the number be a, b and c with a in the hundred position, b in the tens and c in the units position. Given that

he hundreds digit is one more than the ones digit

a = c + 1

c = a - 1

and the tens digit is twice the hundreds digit

b = 2a

If the sum of the digits is 11

a + b + c = 11

substituting

a + 2a + a - 1 = 11

4a - 1 = 11

4a = 11 + 1

4a = 12

a = 12/4

= 3

recall that

c = a - 1 = 3 - 1 = 2

b = 2a = 2 * 3 = 6

Hence the number is 362

For this case we have the following function:

To write in standard form, we follow the following steps:

Step 1:

We solve the binomial squared:

Step 2:

We combine similar terms:

the function, , in standard form is: