In a certain Algebra 2 class of 23 students, 11 of them play basketball and 13 of them play baseball. There are 8 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?

  9/23

Step-by-step explanation:

Of the 23 students, 9 play both baseball and basketball. The probability of choosing one of those is 9/23.

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Let A represent basketball, and B represent baseball. Then ...

  P(A or B) = P(A) +P(B) -P(A and B)

Since 8 students play neither sport, we have ...

  1 -8/23 = 11/23 +13/23 -P(A and B)

  15/23 = 24/23 -P(A and B)

  P(A and B) = (24 -15)/23

  P(A and B) = 9/23

The length is 33 and the Width is 27.

Step-by-step explanation:

So I made it easier by only looking at half of the rectangle. 120 divided by 2 is 60. So out of the length and width, it had to add to equal 60. I plugged in a few numbers and determined 27 and 33. SO, if you add those together it equals 60 while 33 is 6 more meters than 27 and two 27 and two 33 equals 120 for the whole rectangle