jack487
16.03.2020 •
Mathematics
In a certain Algebra 2 class of 26 students, 16 of them play basketball and 9 of them play baseball. There are 5 students who play both sports. What is the probability that a student chosen randomly from the class plays basketball or baseball?
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Ответ:
10/13 ≈ 76.9%
Step-by-step explanation:
P(A∪B) = P(A) +P(B) -P(A∩B)
P(plays basketball ∪ plays baseball)
= P(plays basketball) +P(plays baseball) -P(plays both)
P(plays basketball ∪ plays baseball) = 16/26 +9/26 -5/26 = 20/26 = 10/13
P(plays basketball or baseball) = 10/13 ≈ 76.9%
Ответ:
-14,6 ∈ Q.
Step-by-step explanation: