UratazZ
21.04.2020 •
Mathematics
In a certain Algebra 2 class of 30 students, 18 of them play basketball and 9 of them
play baseball. There are 10 students who play neither sport. What is the probability
that a student chosen randomly from the class plays both basketball and baseball?
Solved
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Ответ:
Probability that a student will play both is 7/30
Step-by-step explanation:
Total students = 30
No. of students who play basketball = 18
Probability that a student will play basketball = 18/30
= 3/5
No. of students who play baseball = 9
Probability that a student will play baseball = 9/30
= 3/10
No. of students who play neither sport = 10
Probability that a student will play neither sport = 10/30
= 1/3
To find :
Probability that a student will play both = p(student will play both)
No.of students who play sport = 30 - 10
= 20
Out of 20 students 18 play basketball and 9 play baseball.
So, some students play both the sports.
No. of students who play both sports = 18 + 9 - 20
= 7
p(student will play both) = 7/30
Probability that a student will play both is 7/30
Ответ:
Step-by-step explanation:
https://drive.google.com/open?id=1QAvmjDjuwgFX0mUdHlWmqMSCJcOVMw2X