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angieplasencia8
16.07.2020 •
Mathematics
In a certain city, the true probability of a baby being a boy is 0.559. Among the next eight randomly selected births, find the probability that at least one of them is a boy. (round to three decimal places)
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Ответ:
99.86%
Step-by-step explanation:
What we have here is a binomial distribution, let x be the baby number among 8 births.
Binomial (n = 8, p = 0.559)
We want to find, P (X ≥ 1)
P (X ≥ 1) = 1 - P (X <1)
P (X ≥ 1) = 1 - P (X = 0)
P (X = 0) = 8C0 * (0.559) ^ 0 * (1 - 0.559) ^ (8-0)]
8C0 = 8! / (0! * (8-0)!) = 1
replacing we have:
P (X = 0) = 1 * 1 * 0.0014
P (X = 0) = 0.0014
P (X ≥ 1)) = 1 - 0.001 4
P (X ≥ 1) = 0.9986
Therefore the probability is 99.86%
Ответ:
100.0 feet
Step-by-step explanation:
For an acute angle in a right triangle, the cotangent function is the ratio of the adjacent side to the opposite side:
cot(16°42') = (distance to goal)/(30 ft)
Multiplying by the denominator, we have ...
(distance to goal) = (30 ft)cot(16°42') = (30 ft)(3.33317) ≈ 100.0 ft
The football is 100.0 feet from the base of the goal.
cot(16°42') = tan(73.3°)