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ShahinF7536
20.02.2020 •
Mathematics
In a certain country, the true probability of a baby being a boy is 0.518. Among the next four randomly selected births in the country, what is the probability that at least one of them is a girl? (Round to three decimal places as needed.)
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Ответ:
0.928 = 92.8% probability that at least one of them is a girl
Step-by-step explanation:
For each baby, there are only two possible outcomes. Either they are boys, or they are not. The probabilities of each baby being a boy is independent from other babies. So we use the binomial probability distribution to solve this problem.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
In this problem we have that:
In a certain country, the true probability of a baby being a boy is 0.518. So![p = 0.518](/tpl/images/0516/8627/8a695.png)
Among the next four randomly selected births in the country, what is the probability that at least one of them is a girl?
Either all four babies are boys, or at least one is girl. The sum of these events is decimal 1. So
We want to find
when
. So
In which
0.928 = 92.8% probability that at least one of them is a girl
Ответ:
yes
Step-by-step explanation:
the points are on a line that passes through the origin. i got it right on the instuction part!