Mathematics: In a dog show, there will be a gold and silver medal awarded.there are 6 finalists. in how many ways can the 2 medals be awarded

We are going to multiply how much she is paid (x) times her hours of work (8 and 6).So the answer is: C. (6+8)x...

In a dog show, there will be a gold and silver

Ответ:

cesargarcia17671

08.01.2022

Step-by-step explanation:

Given: There are six finalists and two medals. That is it asks for the possibilities of 6 finalists taking two at a time. Say, for example the first and third finalist or the second and the sixth finalist and so on. The number of possibilities is given by $ ^nP_r $

$^nP_r = \frac{n!}{(n - r)!}$

So the number of possibilities of 6 finalists taken two at a time is $ ^6P_2 $

$\implies \frac{6!}{(6 - 2)!} = \frac{6!}{4!} \hspace{15mm} [n! = n \times (n-1) \times (n - 2) \times . . . 2 \times 1]$

$\implies \frac{6 \times 5 \times 4 \times \times 3 \times 2 \times 1}{4 \times 3 \times 2 \times 1} = 6 \times 5 = 30$

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In a dog show, there will be a gold and silver medal awarded.there are 6 finalists. in how many ways can the 2 medals be awarded

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