Mathematics: In a geometric sequence, the fourth term is 8 times the first term. the sum of the first 10 terms is 2557.5. find the 10th term of this sequence.

3x - 8 = -23x -8+8 = -2 +83x = 63x/3 = 6/3x = 2sx - 6( 2-6)= -4that is the value of x -6= -4...

In a geometric sequence, the fourth term is 8 times

Ответ:

kenleighbrooke67

24.01.2022

Mathematics

1280

Step-by-step explanation:

The fourth term is 8 times the first term.

The fourth term = ar^3

$ar^{3} = 8a$

To find the common ratio:

∴ $\frac{ar^3}{a} = \frac{8a}{a}\\$

∴ $r^3 = 8\\r = 2\\$

Common ratio = 2

To find the nth number of terms = $\frac{a(r^n -1)}{r-1\\}$

∴ $\frac{a(2^{10} -1)}{2-1}$

∴ $1023a\\$

The sum of 10 terms = 1023a

The sum of 10 terms = 2557.5

∵ 2557.5 = 1023a

∵ $a = \frac{5}{2}$

To find the 10th term:

∴ $ar^9\\$

∴ $\frac{5}{2} *2^9$

⇒ 1280 ║ answer.

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Ответ:

nauticatyson9

24.11.2020

Mathematics

3x - 8 = -2

3x -8+8 = -2 +8

3x = 6

3x/3 = 6/3

x = 2

x - 6

( 2-6)

= -4

that is the value of x -6

= -4

0,0(0 оценок)

In a geometric sequence, the fourth term is 8 times the first term. the sum of the first 10 terms is 2557.5. find the 10th term of this sequence.

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