In a jury pool, 65% of the people are female. Of these 65%, one out of four works in a health field. Find the probability that a random selected person from the jury pool is female and works in a health field.

0.1625

Step-by-step explanation:

We have been given that in a jury pool 65% of the people are female. Of these 65%, one out of four works in a health field. We are asked to find the probability that a random selected person from the jury pool is female and works in a health field.

The probability of selecting a female from jury pool would be .

The probability that a women works in a health field is .

Probability of selecting a person from the jury pool is female and works in a health field would be product of both probabilities.

Therefore, the probability that a random selected person from the jury pool is female and works in a health field would be 0.1625.

7). x = 3.2, AC = 42.8

8). a = 6, YZ = 38

Step-by-step explanation:

It is given in the question that a point B is between A and C of the line segment AC.

⇒ AB + BC = AC

By substituting the values of segments,

5x + (9x - 2) = (11x + 7.6)

14x - 2 = 11x + 7.6

14x - 11x = 7.6 + 2

3x = 9.6

x = 3.2

Therefore, AC = 11x + 7.6

                        = 11(3.2) + 7.6

                        = 35.2 + 7.6

                        = 42.8

Question (8).

If Y is a point between X and Z,

⇒ XY + YZ = XZ

By substituting the measures of these segments given in the question,

(3a - 4) + (6a + 2) = (5a + 22)

9a - 2 = 5a + 22

9a - 5a = 22 + 2

4a = 24

a = 6

Since, length of segment YZ = 6a + 2

                                                = 6(6) + 2

                                                = 38