Mathematics: In a paper bag, 7 of the 15 marbles are yellow. in a cloth bag, 2 of the 15 marbles are yellow. if tim randomly draws one marble from each bag, what is the probability that they are both yellow?

In a paper bag, 7 of the 15 marbles are yellow.

Ответ:

alexabdercmur

09.03.2022

Mathematics

Answer :

$\frac{7}{15}$ × $\frac{2}{15}$ = $\frac{14}{225}$

Step-by-step explanation:

P( $Event_{1}$ ) = choosing yellow marble from paper bag = $\frac{favourable outcomes}{possible outcomes}$ = $\frac{7}{15}$

P( $Event_{2}$ ) = choosing yellow marble from cloth bag = $\frac{favourable outcomes}{possible outcomes}$ = $\frac{2}{15}$

∵ Resultant outcome is dependent upon both the events and both events are independent from each other, so we can apply intersection rule [ P(A∩B)=P(A)×P(B) ] here

∴ Probability ( Both marbles are yellow) = P( $Event_{1}$ ) × P( $Event_{2}$ ) = $\frac{7}{15}$ × $\frac{2}{15}$

0,0(0 оценок)

Ответ:

rcetrangolo

14.03.2021

Mathematics

Step-by-step explanation:

3(9−(4+2)/2)

=(3)(9+−3)

=(3)(9)+(3)(−3)

=27−9

=18

Have a beautiful day!

0,0(0 оценок)

In a paper bag, 7 of the 15 marbles are yellow. in a cloth bag, 2 of the 15 marbles are yellow. if tim randomly draws one marble from each bag, what is the probability that they are both yellow?

Ответ:

Ответ:

Ask your question to the AI advisor

More tips

Answers on questions: Mathematics

Ask an AI advisor a question