smcardenas02
04.10.2021 •
Mathematics
In a particular city 51% of the residents live in a single family home. there are apartments that house an additional 34% and townhouses that house the rest. if 5 residents are randomly selected, determine the following probabilities:
a. all 5 live in an apartment
b. none live in a townhouse
c. at least 1 lives in a single family home
d. 1 lives in an apartment
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Ответ:
x=12
Step-by-step explanation:
The correct question is
Figure ABCD is a rhombus, and m<AEB=7x+6. Solve for x
see the attached figure to better understand the problem
we know that
The diagonals in a rhombus are perpendicular
so
we have that
so
solve for x