![cotybuge2701](/avatars/35421.jpg)
cotybuge2701
16.03.2020 •
Mathematics
In a recent study, researchers found that 31 out of 150 boys aged 7-13 were overweight or obese. On the basis of this study can we conclude that more than 15% of the boys aged 7-13 in the sampled population are overweight or obese? Use a 5% level of significance. Give each of the following to receive full credit: 1) the appropriate null and alternative hypotheses; 2) the appropriate test; 3) the decision rule; 4) the calculation of the test statistic; and 5) your conclusion including a comparison to alpha or the critical value
Solved
Show answers
More tips
- H Health and Medicine What to Do If You Are Bitten by a Dog?...
- A Animals and plants How ants survive winter: exploring the secrets of their winter life...
- F Food and Cooking Discover How to Properly Prepare Dough for Rasstegai...
- P Philosophy Unidentified Flying Object - What is the Nature of this Phenomenon?...
- F Family and Home Protect Your Home or Apartment from Pesky Ants...
- O Other What is a Disk Emulsifier and How Does it Work?...
- F Family and Home What does a newborn need?...
- F Family and Home Choosing the Right Car Seat for Your Child: Tips and Recommendations...
- F Food and Cooking How to Get Reconfirmation of Registration?...
- C Computers and Internet How to Get Rid of Spam in ICQ?...
Answers on questions: Mathematics
- M Mathematics Plzzzzzzzzzz helppppppp...
- M Mathematics Fill in missing information to make the equality true: (... +2a)2 = … +12ab2+4a2....
- M Mathematics The degree of the polynomial f (x) is 3, and the degree of the polynomial g(x) is 4. Find the degree of the polynomial f (x) + g(x)....
- M Mathematics I NEED HELP. Find the IQR for girls scores and boy s scores, as well as the boy s range....
- M Mathematics The MBA program at Florida State University has an enrollment of 160 students with an average age of 34.7 years old and a standard deviation 5.2 years. A random sample...
- M Mathematics Management at a home improvement store randomly selected 7575 customers and observed their shopping habits. They recorded the number of items each of the customers...
- M Mathematics List the integers that satisfy both these inequalities 2x+9 0 x -12 put the answer on the first line WILL GIVE BRAINLIEST IF RIGHT...
- M Mathematics La distancia entre la Tierra y el Sol varía desde 152.1 millones de km hasta 147.1 millones de km. Suponiendo que la ley del Cuadrado Inverso de Newton, F = -GMmr/||r||^3,...
- M Mathematics What is the area of this figure? Use 3.14 for pi. A.6.28 ft2 B.18.28 ft2 C.22.28 ft2 D.28.56 ft2...
- M Mathematics Which equation can be used to find the volume of this solid? A triangular prism. The triangular base has a base of 11 inches and height of 7 inches. The height is 9...
Ответ:
1) Null hypothesis:
Alternative hypothesis:
2) The One-Sample Proportion Test is used to assess whether a population proportion
is significantly different from a hypothesized value
.
3)![z_{crit}= 1.64](/tpl/images/0549/5730/f376e.png)
And the rejection zone would be![z1.64](/tpl/images/0549/5730/6d2b8.png)
4) Calculate the statistic
5) Statistical decision
For this case our calculated value is on the rejection zone, so we have enough evidence to reject the null hypothesis at 5% of significance and we can conclude that the true proportion is higher than 0.15
Step-by-step explanation:
Data given and notation
n=150 represent the random sample taken
X=21 represent the boys overweight
Confidence=95% or 0.95
z would represent the statistic (variable of interest)
1) Concepts and formulas to use
We need to conduct a hypothesis in order to test the true proportion of boys obese is higher than 0.15.:
Null hypothesis:
Alternative hypothesis:
When we conduct a proportion test we need to use the z statistic, and the is given by:
2) The One-Sample Proportion Test is used to assess whether a population proportion
is significantly different from a hypothesized value
.
3) Decision rule
For this case we need a value on the normal standard distribution who accumulates 0.05 of the area on the right tail and on this case this value is:
And the rejection zone would be![z1.64](/tpl/images/0549/5730/6d2b8.png)
4) Calculate the statistic
Since we have all the info requires we can replace in formula (1) like this:
5) Statistical decision
For this case our calculated value is on the rejection zone, so we have enough evidence to reject the null hypothesis at 5% of significance and we can conclude that the true proportion is higher than 0.15
Ответ:
Answer
it's the 3
Step-by-step explanation: