Mathematics: In a small private school, 55 students are randomly selected from 1313 available students. What is the probability that they are the fivefive youngest students?

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In a small private school, 55 students are randomly

Ответ:

ketabug50

30.01.2022

Complete Question

In a small private school, 5 students are randomly selected from 13 available students. What is the probability that they are the five youngest students?

The probability is P(x) = 0.00078

Step-by-step explanation:

From the question we are told that

The number of student randomly selected is r = 5

The number of available students is n = 13

Generally the number of ways that 5 students can be selected from 13 available students is mathematically represented as

$n(k)=\left n} \atop {}} \right.C_r = \frac{n ! }{(n-r ) ! r!}$

substituting values

$\left n} \atop {}} \right.C_r = \frac{13 ! }{(13-5 ) ! 5!}$

$\left n} \atop {}} \right.C_r = \frac{13 * 12 * 11 * 10 * 9 *8! }{8 ! * 5 * 4 * 3 * 2 *1}$

$\left n} \atop {}} \right.C_r = 1287$

The number of method by which 5 youngest students are selected is n(x) = 1

Then the probability of selecting the five youngest students is mathematically represented as

$P(x) = \frac{n(x)}{n(k)}$

substituting values

$P(x) = \frac{1}{1287}$

P(x) = 0.00078

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In a small private school, 55 students are randomly selected from 1313 available students. What is the probability that they are the fivefive youngest students?

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