Mathematics: In a test of physical fitness, a group of men ages 65 and older from a local retirement community were told to do as many sit-ups as they could. It is known the population meanis 20 with The scores for the men from the retirement community are given below. Use a two-tailed rejection region with a total area of 0.05. What is the sample mean? 24 25 10 23 18 29 47 32 19 24 20 28 21 20 27 25

1.5 tons equals 48000 because there are 32001 tons in 32 - x 2 equals 16 + 16 x 2 equals 32 + 32 Plus teen equals 48...

In a test of physical fitness, a group of men ages

bmr12

22.01.2022

The sample mean = 24.5

Step-by-step explanation:

Solution:

Using the one sample z test

Since the test is a two tailed test

Null hypothesis, H₀: μ = 20.

Alternative hypothesis, Ha: µ ≠ 20

The test statistic formula is given by:

$z = \frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n} } }$

The population mean, µ = 20

The sample mean, $\bar{x} = \frac{\sum x}{n}$

n = 16

$\bar {x} = \frac{24 + 25 + 10 + 23 + 18 + 29 + 47 + 32 + 19+24+20+28+21+20+27+25}{16}$

$\bar {x} = \frac{392}{16} \\\bar {x} = 24.5$

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