In AQRS,QR = SQ and mZQ = 121°. Find mZS.

The solutions are (2,0) and (3,0)

Step-by-step explanation:

The common denominator is (x - 2)(x - 4) which comes to x^2 - 6x + 8 which is exactly what the denominator on the right hand side is.

2x (x - 4) - (x+3)(x - 2)      =    - 4x

(x -2)(x - 4)                            x^2 - 6x - 8

Multiply both sides by x^2 -6x - 8

2x(x - 4) - (x^2 + x - 6 ) = - 4x       Remove the brackets

2x^2 - 8x - x^2 - x + 6  = - 4x       Combine like terms on the left

2x^2 - x^2 - 8x - x + 6 =  - 4x

x^2 - 9x + 6 = - 4x                        Add 4x from both sides

x^2 - 9x + 4x + 6 = 0

x^2 - 5x + 6 = 0

This factors into

(x - 2) and (x - 3)

x - 2 = 0

x = 2

x - 3  = 0

x = 3